The period of `cosx^2` is

Explanation

A function is periodic if `f(x) = f(x+T)`.


Let us assume that `cos(x^2)` has a period of T. In that case:

`cos(x+T)^2 = cosx^2`

`=>(x+T)^2 = 2npi+x^2`

`=>x^2+T^2+2xT= 2npi+x^2`

`=>T^2+2xT-2npi = 0`

As we can see, `T` is dependent on the value of `x` and hence, is not a constant. So `cos(x^2)` is not periodic.

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