[" 4.यदि "(a,0),(0,b)" And "(x,y)" Align हों,तो Prove that "-],[qquad bx+ay=ab" ."]

If the points (x,y),(a,0) and (0,b) are collinear, prove that x/a + y/b = 1, ab ne 0

Solve: ax - by = 1 bx + ay = 0

y=e^(ax)sin bx : Prove that y_2-2ay_1+(a^2+b^2)y=0 .

Prove that (ab+xy)(ax+by)>4abxy(a,b,x,y>0)

If the point (x,y) be equidistant from the points (a+b,b-a) and (a-b,a+b) , prove that bx =ay .

If distances of a point (x, y) are equidistant from (a +b, b-a) and (a- b, a + b), prove that bx = ay.

If (ay-bx)/c = (cx - az)/b = (bz - cy)/a , " then prove that " x/a = y/b = z/c .

If the point P(x, y) is equidistant from the points A(a + b, b - a) and B(a - b, a + b). Prove that bx = ay.

If the point P (x, y) is equidistant from the points A (a + b, b - a) and B(a -b, a + b). Prove that bx = ay.

If the point P(x, y) is equidistant from the points A(a + b, b-a) and B(a-b, a + b). Prove that bx = ay.