(a)/(x)-(b)/(y)=0,(ab^(2))/(x)+(a^(2)b)/(y)=(a^(2)+b^(2))," where "x!=0" and "y!=0

Solve the following system of equations in x and y:(a)/(x)-(b)/(y)=0,quad (ab^(2))/(x)+(a^(2)b)/(y)=a^(2)+b^(2) where x,y!=0

Solve : {:((a)/(x)-(b)/(y)=0),((ab^(2))/(x)+(a^(2)b)/(y)=a^(2)+b^(2)):}

{:((a^(2))/(x) - (b^(2))/(y) = 0),((a^(2)b)/(x)+(b^(2)a)/(y) = "a + b, where x, y"ne 0.):}

{:((a^(2))/(x) - (b^(2))/(y) = 0),((a^(2)b)/(x)+(b^(2)a)/(y) = "a + b, where x, y"ne 0.):}

Solve the following system of equations in x and y : a/x-b/y=0,\ \ \ \ (a b^2)/x+(a^2b)/y=a^2+b^2 , where x ,\ y!=0 .

Solve the following pair of equations for x and y : (a^(2))/(x)-(b^(2))/(y)=0, (a^(2)b)/(x)+(b^(2)a)/(y)=a+b , x ne 0 , y ne 0 .

Solve the following system of equations by method of cross-multiplication: (a^(2))/(x)-(b^(2))/(y)=0,quad (a^(2)b)/(x)+(b^(2)a)/(y)=a+b,quad x,y!=0

(x)/(a)+(y)/(b)=a+b(x)/(a^(2))+(y)/(b^(2))=2,a!=0,b!=0

Solution to (a^2)/(x)-(b^2)/(y)=0, (a^2b)/(x)+(b^2a)/(y)=a+b,x ne0,y ne0 is………

(a-b)x+(a+b)y=a^(2)-2ab-b^(2)(a+b)(x+y)=a^(2)+b^(2) find x and y