The force on a particle of mass `10g` is `(hati 10+hatj 5)`N If it starts from rest what would be its position at time `t=5s` ?

The force on a particle of mass 10 g is (veci10 + vecj5)N . If it starts from rest what would be its position at time t=5s?

The force on a particle of mass 10 g is (veci10 + vecj5)N . If it starts from rest what would be its position at time t=5s?

The force on a particle of mass 10 g is (veci10 + vecj5)N . If it starts from rest what would be its position at time t=5s?

The force on a particle of mass 10 g is (10 hat(i) + 5 hat(j)) N. If it starts from rest what would be its position at time t = 5s ?

A force of (6hati+8hatj) N acted on a body of mass 10 kg. The displacement after 10 sec, if it starts from rest, will be -

A force of 200 dyne acts on a body of mass 10 g for 5 s. What will be the velocity of the body if it starts from rest ? Express in SI unit .

A force vec(F) = (40 hat (i) + 10 hat(j)) N acts on body of mass 5 kg. If the body starts from rest, its position vector vec(r) at time t = 10 s, will be

A force of 10 N acts on a body of mass 0.5 kg for 0.25s starting from rest.What is its momentum now?

A force of 10 N acts on a body of mass 0.5 kg for 0.25s starting from rest.What is its momentum now?