litis le f*

Let f(1)=-2, f'(x) ge4.2 for 1le x le6 . The smallest possible value of f(6)-16 is ……..

Let f(1)=-2, f'(x) ge4.2 for 1le x le6 . The smallest possible value of f(6)-16 is ……..

Suppose that for a function f(x), f(x) le 1 for all 1 le x le 4 . Show that f(4)-f(1) le 3

A={x:-1 le x le 1}, f: A to A defined by f(x) =x|x| . Then f is:

Let A={-1 le x le 1} and f:A to A such that f(x)=x|x| then f is:

Let A={x-1 le x le 1} and f:A to A such that f(x)=x|x| then f is:

Let A={-1 le x le 1} and f:A to A such that f(x)=x|x| then f is:

Disuss the continuity of the function f where f is defined by f(x) {{:(3 if 0 le x le 1 ),(4 if 1 lt x lt 3 ),(5 if 3 le x le 10 ):}

Discuss the continuity of the function f, where f is defined by f(x){{:(3"," if 0 le x le 1),(4"," if 1lt x lt 3 ),(5"," if 3 le x le 10):}