`int(cos8x-1)/(tan2x-cot2x)dx`

If Integration using trigonometric identities : int(cos 8x+1)/(tan2x-cot 2x)dx=acos 8 x+c then a = ..........

If : int(1+cos8x)/(tan2x-cot2x)dx=a.cos8x+c, then : a=

If int(1+cos8x)/(tan2x- cot2x)dx= acos8x +c , then find the value of a.

If in(cos8x+1)/(tan 2x-cot 2x) dx =a cos 8x +c then a=

If (1+cos8x)/(tan2x-cot2x)dx=acos8x+C ,then a=

If the integral int(cos8x+1)/(cot2x-tan2x)dx=Acos8x+k , where k is an arbitrary constant, then A is equal to

If int ( 1+cos 8x)/( tan 2x-cot 2x)dx = k cos 8x+ C , then k equals

In the integral int(cos 8x+1)/(cot 2x-tan 2x)dx=A cos 8x+k , where k is an arbitrary constant,then A is equal to

int(1+cos4x)/(cot x-tan x)dx