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Let ` vec a , vec b , vec c , vec d` be the position vectors of the four distinct points `A , B , C , Ddot` If ` vec b- vec a= vec a- vec d ,` then show that `A B C D` is parallelogram.

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Given :
`vec{vec{b}}, vec{vec{b}}, vec{vec{c}}, vec{vec{d}}` are the position vectors of the four distinct points A, B, C, D
So ,`vec{ABCD}` will be a quadrilateral
And also here we get ,
`vec{vec{b}}-vec{vec{a}}=vec{vec{c}}-vec{vec{d}}`
...
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