(sec^(2)(90^(@)-theta)-cot^(2)theta)/(2(sin^(2)25^(@)+sin^(2)65^(@)))+(2sin^(2)30^(@)tan^(2)32^(@)*tan^(2)58^(@))/(3(sec^(2)33-cot^(2)57))

Evaluate: (sec^(2)(90^(@) - theta)-cot^(2) theta)/(2 (sin^(2) 25^(@)+sin^(2) 65^(@)))+(2 sin^(2)30^(@)tan^(2) 32^(@) tan^(2)58^(@))/(3(sec^(2)33^(@)-cot^(2)57^(@))) .

Evaluate the following.(sec^(2)(90-theta)-cot^(2)theta)/(2(sin^(2)25^(@)+sin^(2)65^(@)))-(2cos^(2)60tan^(2)28^(@)tan^(2)62)/(3(sec^(2)43^(@)-cot^(2)47^(@)))

Without using Trigonometric Tables evaluate the following :- (sec^2(90^@-theta)-cot^2theta)/(2[sin^2 25^@+sin^2 65^@]) +(2cos^2 60^@tan^2 28^@tan^2 62^@)/(3[sec^2 43^@-cot^2 47^@] .

Evaluate : (sec^(2)theta-cot^(2)(90^(@)-theta))/("cosec"^(2)67^(@)-tan^(2)23^(2))+(sin^(2)40^(@)+sin^(2)50^(@))

Evaluate : (sec^(2)theta-cot^(2)(90^(@)-theta))/("cosec"^(2)67^(@)-tan^(2)23^(2))+(sin^(2)40^(@)+sin^(2)50^(@))

The value of cottheta.tan(90^(@)-theta)-sec(90^(@)-theta)cosectheta+(sin^(2)25^(@)+sin^(2)65^(@)) is

If x=sec57^(@) , then cot^(2)33^(@)+sin^(2)57^(@)+sin^(2)33^(@)+cosec^(2)57^(@)cos^(2)33^(@)+sec^(2)33^(@)sin^(2)57^(@) is equal to:

(sec theta+csc theta)^(2)-(tan theta+cot theta)^(2)=

cot theta=(2tan7(1)/(2^(@)))/(1-tan^(2)7(1)/(2^(@))) then sin3 theta=