Writhe the angle between two vectors ` vec a\ a n d\ vec b"\ "` with magnitudes `sqrt(3)\ a n d\ 2` repsectively having ` vec adot vec b=sqrt(6)` .

Explanation

Given: `vec{a}=sqrt{3},vec{b}=2`


Given: `vec{a} cdot vec{b}=sqrt{6}`


`vec{a} cdot vec{b}=vec{a}vec{b} cos theta`


Hence,` sqrt{6}=sqrt{3} times 2 times cos theta`


`Rightarrow cos theta=frac{sqrt{6}}{sqrt{3} times 2} `


`Rightarrow cos theta=frac{1}{sqrt{2}} `


`Rightarrow theta=frac{pi}{4}`


Therefore, the angle between the given vectors `vec{a} and vec{b} is frac{pi}{4}`.