Show that the area of a parallelogram having diagonals `3 hat i+ hat j-2 hat k\ a n d\ hat i-3 hat j+4 hat k` is `5sqrt(3)` square units.

Explanation

To find the area of the parallelogram with given diagonals represented as vectors, we can follow these steps:

### Step 1: Define the diagonals as vectors
Let the diagonals of the parallelogram be represented by the vectors:
- \( \mathbf{a} = 3\hat{i} + \hat{j} - 2\hat{k} \)
- \( \mathbf{b} = \hat{i} - 3\hat{j} + 4\hat{k} \)

### Step 2: Use the formula for the area of the parallelogram
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