If `theta` is the angle between the vectors `2 hat i-2 hat j+4 hat k\ a n d\ 3 hat i+ hat j+2 hat k ,` then `sintheta=` `2/3` b. `2/(sqrt(7))` c. `(sqrt(2))/7` d. `sqrt(2/7)`

Explanation

$$ \begin{aligned} &\text{Let}\quad\vec{a}=2 \hat{i}-2 \hat{j}+4 \hat{k}\\ &\text{And}\quad\vec{b}=3 \hat{i}+\hat{j}+2 \hat{k} \end{aligned} $$
$$
\begin{aligned}
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