Find the Cartesian equation of a line passing through (1, -1, 2) and parallel to the line whose equations are `(x-3)/1=(y-1)/2=(z+1)/2dot` Also, reduce the equation obtained in vector form.

Explanation

The cartesian equation of the line is


``
`frac{x-1}{1}=frac{y-(-1)}{2}=frac{z-2}{-2}`


``
Let this be equal to `lambda`


`frac{x-1}{1}=frac{y-(-1)}{2}`


`=frac{z-2}{-2}=lambda`


`{x}=1+lambda`,
`{y}=-1+2 lambda`,

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