Find the direction cosines of the line `(x+2)/2=(2y-7)/6=(1-z)/(-3)` . Also, find the vector equation of the line through the point `A(-1,\ 2,\ 3)` and parallel to the given line.

Explanation

Given:

line is `frac{x+2}{2}=frac{2 y-7}{6}=frac{5-z}{6}`


`rightarrow frac{x+2}{2}=frac{y-7 / 2}{3}=frac{z-5}{-6}`


So, Direction ratios of the line are 2,3,-6

If a, b, c are the direction ratios of a line then direction cosines are


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