Find the cartesian equation of the line which passes through the point `(-2,4,-5)` and parallel and line are `(3,5,6)`. So, the equation of line is,
`(x-(-2))/(3) = (y-4)/(5) = (z-(-5))/(6)`.

Explanation

The general equation of line is `(x-x_1)/(alpha) =(y-y_1)/(beta) = (z-z_1)/(gamma)`

Hence the equation of line through point (3,5,6) is

`(x+3)/(3) = (y-4)/(5) = (z+8)/(6)`

Now the another point through which line passes is (-2,4,-5)

Then the equation of line is
`(x-(-2))/(3) = (y-4)/(5) = (z-(-5))/(6)`

`(x+2)/(3) = (y-4)/(5) = (z+5)/(6)`