The length of the perpendicular drawn from `(1,2,3)` to the line `(x-6)/3=(y-7)/2=(z-7)/(-2)` is a. `4` b. `5` c. `6` d. `7`

Explanation

We have to find the length of the
perpendicular drawn from `(1,2,3)`
to the line `(x-6)/3=(y-7)/2=(z-7)/(-2)`

So, a point on line `(3lambda+6,2lambda+7,-2lambda+7)`

Then the direction ratio's of line which is perpendicular to given line

`(3lambda+6−1,2lambda+7-2,-2λ+7-3)`

`(3lambda+5,2lambda+5,−2lambda+4)`

Now as the direction ratio's of given line are 3,2,-2

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