Reduce the equation of the plane `2x+3y-4=12` to intercept form and find its intercepts on the coordinate axes.

Explanation

The given plane is `2x+3y-4z=12`

We can write this equation as

`x/6+y/4+z/(-3)=1 ldots`(i)

Then the equation of plane whose intercepts on the coordinate axes are a,b,c is

`x/a+y/b+z/c=1 ldots`(ii)

On comparing (i) and (ii) we get

`a=6,b=4,c=-3`