Find the vector equation of the plane whose Cartesian form of equals `3x-4y+2z=5.`

Explanation

The given plane is `3x-4y+2z=5.`

Then the vector equation of the plane is

`(xhat(i)+yhat(j)+zhat(k)).(3hat(i)-4hat(j)+2hat(k))=5`

`vec(r).(3hat(i)-4hat(j)+2hat(k))=5`

Hence this is the required vector equation of given plane.