Find the angles at which the normal vector to the plane `4x+8y+z=5` is inclined to the coordinate axes.

Explanation

Let `\vec {{n}}` be a vector normal to the plane. Since direction ratios of normal to the plane are proportional to `4,8,1.`


Therefore, `\vec {{n}}=4 \hat{{i}}+8 \hat{{j}}+\hat{{k}}`


Direction cosines of `\vec {{n}} `are


`\frac{4}{9}, \frac{8}{9}, \frac{1}{9}`


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