If the axes are rectangular and `P` is the point (2, 3, -1), find the equation of the plane through `P` at right angle to `O Pdot`

Explanation

To find the equation of the plane through the point \( P(2, 3, -1) \) that is perpendicular to the vector \( \overrightarrow{OP} \), we can follow these steps:

### Step 1: Identify the point and the vector
The point \( P \) is given as \( (2, 3, -1) \). The origin \( O \) is at \( (0, 0, 0) \). The vector \( \overrightarrow{OP} \) can be calculated as:
\[ \overrightarrow{OP} = P - O = (2 - 0, 3 - 0, -1 - 0) = (2, 3, -1) \]

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