Find the intercepts made on the coordinate axes by the plane `2x+y-2z=3` and find also the direction cosines of the normal to the plane.

Explanation

The given equation of the plane is `2 x+y-2 z=3`



`\Rightarrow \frac{x}{\frac{3}{2}}+\frac{y}{3}+\frac{z}{\frac{-3}{2}}=1`



We know that the equation of the plane whose intercepts on the coordinate axes are


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