Find the equation of the plane that bisects the line segment joining points (1, 2, 3) and (3, 4, 5) and is at right angle to it.

Explanation

The given points are `A(1,2,3)` and `B(3,4,5)`


The line segment `A B` is given by` (x_{2}-x_{1}) (y_{2}-y_{1}), (z_{2}-z_{1})`

The line segment `{AB}` is given by` (3-1),(4-2),(5-3)=(2,2,2)`


Since the plane bisects `{AB}` at rightangles,` {{AB}}` is the normal to the plane which is {{n}}



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