Write the normal form of the equation of the plane `2x-3y+6z+14=0.`

Explanation

Equation of the plane is `2 x-3 y+6 z+14=0`


or


`2 x-3 y+6 z=-14`


Dividing with` \sqrt{2^{2}+(-3)^{2}+6^{2}}=\sqrt{4+9+36}=\sqrt{49}=7`


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