Find the angle between the plane: `2x-3y+4z=1\ a n d-x+y=4.`

Explanation

Here , Given planes are 2 x-3 y+4 z=1 and -x+y=4

It is known that angle between two planes,

`a_{1} x+b_{1} y+c_{1} z+d_{1}=0`

`a_{2} x+b_{2} y+c_{2} z+d_{2}=0` is given as


`cos theta=frac{a_{1} a_{2}+b_{1} b_{2}+c_{1} c_{2}}{sqrt{a_{1}^{2}+b_{1}^{2}+c_{1}^{2}} sqrt{a_{2}^{2}+b_{2}^{2}+c_{2}^{2}}}`


So, we have,

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