Find the equation of the plane passing through the point (-1,3,2) and perpendicular to each of the planes `x+2y+3z=5 and 3x+3y+z=0`

Explanation

Here, The equation of plane passing through `(x_{1}, y_{1}, z_{1})` is given by

`A(x-x_{1})+B(y-y_{1})+C(z-z_{1})=0`


where, A, B, C are the direction ratios of normal to the plane.

Now ,the plane passes through (-1,3,2)

Therefore, equation of plane is


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