Find the equation of the plane passing through the line intersection of the plane: `vec2x-y=0 and 3z-y=0` and perpendicular to the plane `4x+5y-3z=8`

Explanation

Any plane through the line of intersection of the planes:


`2x-y=0` and `3z - y =0` is given by


`(2x – y) + lambda(3z – y) =0 ldots (i)`


`2x + (-1 –lambda)y + 3zlabda =0` is perpendicular to the plane `4x + 5y + 3z=0`


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