Find the distance of the point (2, 3, -5) from the plane `x+2y-2z-9=0.`

Explanation

To find the distance of the point (2, 3, -5) from the plane given by the equation \(x + 2y - 2z - 9 = 0\), we can use the formula for the distance \(D\) from a point \((x_1, y_1, z_1)\) to a plane \(Ax + By + Cz + D = 0\):

\[ D = \frac{|Ax_1 + By_1 + Cz_1 + D|}{\sqrt{A^2 + B^2 + C^2}} \]

### Step-by-Step Solution:

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