Write the intercepts made by the plane `2x-3y+4z=12` on the coordinate axes.

Explanation

`\frac{x}{a}+\frac{y}{b}+\frac{z}{c}=1`


According to the question`\quad 2 x-3 y+4 z=12`


`\frac{2 x}{12}-\frac{3 y}{12}+\frac{4 z}{12}=1`


`\frac{x}{6}+\frac{y}{4}+\frac{z}{3}=1`


Hence,`\quad a=6.1`


`b=-4 .`
`c=3 .`