From a pack of 52 cards, two are drawn one by one without replacement. Find the probability that both of them are kings.

Explanation

Total number of all favorable cases is `n(S)=52`

Let `A` be the event that first card drawn is a king. There are four kings in the pack. Hence, the probability of the first card is a king is

`P(A)=frac{4}{52}`

Let `B` be the event that second card is also king without replacement. Then there are 3 kings in the pack as the cards are not replaced. Therefore, the probability of the second card is also king is

`P(B | A)=frac{3}{51}`

Then the probability of getting two kings without replacement is


`=P(A) P(B | A) `

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