In a hostel 60% of the students read Hindi news paper, 40% read English newspaper and 20% read both Hindi and English newspapers. A student is selected at random.Find the probability that she reads neither Hindi nor English news paper ?

Explanation

Suppose H represents the students who read Hindi newspaper and E representn the who read English newspaper.


We have,
`
P(H)=60 %=frac{6}{10}=frac{3}{5}`

`
P(E)=40 %=frac{40}{100}=frac{2}{5}`

`
P(H cap E)=20 %=frac{20}{100}=frac{1}{5}`



Probability of that a student reads Hindi or English newspaper is,



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