Refer to question 1 above. If the die were fair, determine whether or not the events A and B are independent.

Explanation

`A={(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)}`

` therefore {n}({A})=6 and {n}({S})=6 times 6=36`


So,` {P}({A})=frac{{n}({A})}{{n}({S})}=frac{6}{36}=frac{1}{6}`


`B={(4,6),(6,4),(5,5),(5,6),(6,5),(6,6)}`

`
n(B)=6 and n(S)=36`

`

therefore P(B)=frac{n(B)}{n(S)}=frac{6}{36}=frac{1}{6}`

`

A cap B={(5,5),(6,6)}`

`
...