An unbiased die is tossed twice. Find the probability of getting 4, 5, 6 on the first toss and 1, 2, 3 or 4 on the second toss.

Explanation

`P(A)`=P(4,5 or 6 on first toss )`=frac{18}{36}=frac{1}{2}`


`P(B)`=P(1,2,3 or 4 on second toss )`=frac{24}{36}=frac{2}{3}`


Since, A and B are independent events.


`Rightarrow P(A cap B)=P(A) P(B) `


`Rightarrow P(A cap B)=frac{1}{2} times frac{2}{3} `


Hence,` P(A cap B)=frac{1}{3}`