Two balls are drawn at random with replacement from a box containing 10 black and 8 red balls. Find the probability that i. both balls are red, ii. first ball is black and second is red, iii. One of them is black and other is red.

Explanation

Given:


Total number of balls =18


Number of red balls =8


Number of black balls =10


(i) Probability of getting a red ball in tfirst draw `=\frac{8}{18}=\frac{4}{9}`


The ball is replaced after the first draw.


Hence, Probability of getting a red ball in second draw `=\frac{8}{18}=\frac{4}{9}`


Hence, probability of getting both the balls red `=\frac{4}{9} \times \frac{4}{9}=\frac{16}{81}=0.19`


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