An urn contains 4 red and 7 black balls. Two balls are drawn at random with replacement. Find the probability of getting i. 2 red balls, ii. 2 black balls, iii. One red and one black ball.

Explanation

To solve the problem step by step, we will calculate the probabilities of drawing two red balls, two black balls, and one red and one black ball from the urn containing 4 red and 7 black balls.

### Step 1: Determine the total number of balls
The total number of balls in the urn is:
\[ 4 \text{ (red)} + 7 \text{ (black)} = 11 \text{ (total balls)} \]

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