The probabilities of two students A and B coming to the school in time are `3/7"\ "` and `5/7` respectively. Assuming that the events, A coming in time and B coming in time are independent, find the probability of only one of them coming to the school in time. Write at least one advantage of coming to school in time.

Explanation

According to question , it is Given that :

`since` P(A)= probability of A coming in time `=frac{3}{7}`

`since` P(B)= Probability of B coming in time` =frac{5}{7}`

`therefore` Probability of only one of them coming to the school in time `=P(A cap bar{B})+
{P}(overline{{A}} cap {B})`

`={P}({A}) {P}(overline{{B}}+{P}(overline{{A}}) {P}({B}))`

`=frac{3}{7}(1-frac{5}{7})+(1-frac{3}{7}) frac{5}{7}[{P}(overline{{E}}=1-{P}({E})]`

`=frac{26}{49}`

...