A speaks truth in 75% and B in 80% of the cases. In what percentage of cases are they likely to contradict each other in narrating the same incident?

Explanation

To find the percentage of cases in which A and B are likely to contradict each other when narrating the same incident, we can follow these steps:

### Step 1: Determine the probabilities of A and B speaking the truth and lying.
- Probability that A speaks the truth (P(A)) = 75% = 0.75
- Probability that A lies (P(A')) = 1 - P(A) = 1 - 0.75 = 0.25

- Probability that B speaks the truth (P(B)) = 80% = 0.80
- Probability that B lies (P(B')) = 1 - P(B) = 1 - 0.80 = 0.20
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