A manufacturer has three machine operators A, B and C. The first operator A produces 1% defective items, where as the other two operators B and C produce 5% and 7% defective items respectively. A is on the job for 50% of the tune, B is on the job

Explanation

`E_{1}`=time taken by machine operator A.


`E_{2}`= time taken by machine operator B.


`E_{3}`= time taken by machine operator C.



`X`=PRODUCING DEFECTIVE ITEMS

`
therefore P(E_{1})=50 `

`
P(E_{2})=30`

`
P(E_{3})=20`

`
...