The probability that a leap year will have `53` Fridays or `53` Saturday is

Options

A. a) `2/7`
B. b) `3/7`
C. c) `4/7`
D. d) `1/7`

Answer

b) `3/7`

Explanation

We know,

Let `X=` the leap year has `53` Fridays or `53` Saturdays.

`n(E)=3`


Leap year `= 52` weeks and `2` days


Sample space for two days: {(Sunday, Monday), (Monday, Tuesday), (Tuesday, Wednesday), (Wednesday, Thursday), (Thursday, Friday), (Friday, Saturday), (Saturday, Sunday)};


`n(S)=7`


`p=(n(X))/(n(S))=3/7`


Hence, correct option is b)