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A box contains 6 nails and 10 nuts. Half...

A box contains `6` nails and `10` nuts. Half of the nails and half of the nuts are rusted. If one item is chosen at random, then find the probability that it is rusted or is a nail.

Text Solution

Verified by Experts

Let,

`A=` Event of rusted item chosen

`B=` Event of nail chosen.

`P(A)=8/16`

`P(B)=6/16`

`P(AnnB)=3/16`

We know,

`P(AuuB)=P(A)+P(B)−P(AnnB)`

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