The probability that in a year of `22nd` century chosen at random, there will be `53` Sundays is

Explanation

Probability of occurrence of leap year in `100` year `= 25/100 = 1/4`


`P(A)=1/4`


`P(A') = 1-1/4 = 3/4`


We know,


Leap year `= 366` days or `52` weeks and `2` days.


Sample space `= {(Sunday, Monday), (Monday, Tuesday), (Tuesday, Wed n e s day), (Wed n e sday, Thursday), (Thursday, Friday), (Friday, Saturday), (Saturday, Sunday)}`


Probability of occurrence of 53 Sundays in a leap year `= 2/7`


Probability of occurrence of 53 Sundays in non-leap year `= 1/7`


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