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If P(A)=3/10 , P(B)=2/5 and P(AuuB)=3/5 ...

If `P(A)=3/10` , `P(B)=2/5` and `P(AuuB)=3/5` then `P(A//B)+P(B//A)` equals

A

a) `1/4`

B

b) `7/12`

C

c) `5/12`

D

d) `1/3`

Text Solution

Verified by Experts

The correct Answer is:
b) `7/12`
Given, `P(A)=3/10` , `P(B)=2/5` and `P(AuuB)=3/5`

`P(AuuB)=P(A)+P(B)-P(AnnB)`

`3/5=3/10+2/5-P(AnnB)`

`P(AnnB)=1/10`

`P(B//A)=(P(AnnB))/(P(A))=(1/10)/(3/10)=1/3`

`P(A//B)=(P(AnnB))/(P(B))=(1/10)/(2/5)=1/4`

...
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