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A bag containing 5 red and 3 blue balls....

A bag containing `5` red and `3` blue balls. If `3` balls are drawn at random without replacement the probability that exactly two of the three balls were red, the first being red is

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Let,

`E_1=` First red ball

`E_2=` Exactly `2` of `3` balls are red

`P_R=` red ball, `P_B=`blue ball

`P(E_1)=P_R*P_R*P_R+P_R*P_R*P_B+P_R*P_B*P_R+P_R⋅P_B⋅P_B`

`=5/8*4/7*3/6+5/8*4/7*3/6+5/8*3/7*4/6+5/8*3/7*2/6`

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