A box contains `3` orange balls, `3` green balls and `2` blue balls. Three balls are drawn at random from the box without replacement. The probability of drawing `2` green balls and one blue ball is

Options

A. a) `(167)/(168)`
B. b) `(1)/(28)`
C. c) `(2)/(21)`
D. d) `(3)/(28)`

Answer

d) `(3)/(28)`

Explanation

Probability of drawing `2G` balls and `1B` balls:


`=P(G)*P(G)*P(B)+P(B)*P(G)*P(G)+P(G)*P(B)*P(G)`


`=3/8*2/7*2/6+2/8*3/7*2/6+3/8*2/7*2/6`


`=3/28`



Hence, correct option is d)