There are 5% defective items in a large bulk of items. What is the probability that a sample of 10 items will include not more than one defective item?

Explanation

Let `X` = Number of defective items

`p=` Probability of defective items

`therefore p=5 %=frac{5}{100}=frac{1}{20} `

`text { and } q=1-p=1-frac{1}{20}=frac{19}{20} `

`therefore X sim B(10, frac{1}{20})`

The` p.m.f.` of ` X` is given by


`{P}({X}={x})=^{n} C_{x} p^{x} q^{n-x}`

...