Determine the binomial distribution whose mean is `9` and variance `9/4`.

Explanation

It is given that mean, i.e. `n p=9 ` and variance, i.e.` n p q=frac{9}{4}`

`therefore frac{{npq}}{{np}}=frac{9}{4} times frac{1}{9}=frac{1}{4}`

Hence, `q=frac{1}{4}`

And ` p=1-q=frac{3}{4}`

When` {p}=frac{3}{4},`

`{np}=frac{3 n}{4} `

`9=frac{3 {n}}{4} `

`Rightarrow {n}=12 `

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