If the sum of the mean and variance of a binomial distribution for 5 trials is `1.8`; find the distribution.

Explanation

Let `{n} ` and {`p`} be the parameters of the distribution. Then,

Mean `={np}` and Variance `={npq`}

Given,

`{n}=5 text { and, Mean }+text { Variance }=1.8 `

`{np}+{npq}=1.8 `

`5 {p}+5 {pq}=1.8 `

`5 {p}+5 {p}(1-{p})=1.8 `

`5 {p}^{2}-10 {p}+1.8=0 `

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