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The mean and variance of a random variab...

The mean and variance of a random variable X having a binomial distribution are `4 and 2` respectively. The `P(X=1)` is

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Given:
Mean `=4 = np`
Variance `=npq= 2`
`Rightarrow q=1/2 Rightarrow p=1/2`
`n=4/p = 8`
`P(X=1) = 8 *C_1 p^1q^(8-1) = 8*1/2*1/(2)^7 = 1/32`
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