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If in a binomial distribution n=4 \ and ...

If in a binomial distribution `n=4 \ and \ P(X = 0) = (16)/(81)`, find `q` .

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Verified by Experts

Let p be the probability of success and q that of failure in trial
Then,
`P(X=0) = \ ^4C_0p^0q^4 = 14/81`
`Rightarrow q^4 = (2/3)^4 (As \ ^n C_0 =1)`
`Rightarrow q=2/3`
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