If `X` follows binomial distribution with parameters `n=5,\ p\ a n d\ P(X=2)=9 \ P(X=3)`, then find the value of `p` .

Explanation

`therefore P(X=2) = 9`


`P(X=3)` `(` where, `n=5` and `q=1-p)`


`Rightarrow \ ^5 C_2 p^2 (1-p)^3 = 9 * \ ^ 5C_3 p^3 (1-p)^2`


`Rightarrow 5!/(2!*3!) p^2 (1-p)^3 = 9 * 5!(3!*2!) p^3 (1-p)^2`


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