Find the probability distribution of the number of white balls drawn in a random draw of 3 balls without replacement from a bag containing 4 white and 6 red balls.

Explanation

According to question:

Let {X} denote the number of white balls in a sample of 3 balls drawn from a bag containing 4 white and 6 red balls.

So, {X} can take the values 0 white ball 1 or 2 or 3 white ball.


`Rightarrow {P}({X}=0)=frac{{ }^{6} {C}_{3}}{{ }^{10} {C}_{3}}`



`=frac{frac{6 !}{3 ! 3 !}}{frac{10 !}{3 ! 7 !}} `

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