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A dealer in refrigerators estimates from...

A dealer in refrigerators estimates from his past experience the probabilities of his selling refrigerators in a day. These are as follows: No of refrigerators sold in a day: 0 1 2 3 4 5 6 Probability 0.03 0.20 0.23 0.25 0.12 0.10 0.07 Find the mean number of refrigerators sold in a day.

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According to given question:
Let X denotes the number of refrigerators sold in a day. Then, the probability distribution of X is `x_{i}: quad 0 quad 1 quad 2 quad 3 quad 4 quad 5 quad 6`
`p_{i}: 0.03 0.20 0.23 0.25 0.12 0.10 0.07 `
therefore `quad bar{X}=0.03 times 0+0.20 times 1+0.23 times 2+0.25 times 3+0.12 times 4+0.10 times 5+ ...
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